This does indeed seem to be equal to intdiv:
<?php
function intdiv_1($a, $b){
return ($a - $a % $b) / $b;
}
?>
However, this isn't:
<?php
function intdiv_2($a, $b){
return floor($a / $b);
}
?>
Consider an example where either of the parameters is negative:
<?php
$param1 = -10;
$param2 = 3;
print_r([
'modulus' => intdiv_1($param1, $param2),
'floor' => intdiv_2($param1, $param2),
]);
/**
* Array
* (
* [modulus] => -3
* [floor] => -4
* )
*/
?>
intdiv
(PHP 7)
intdiv — Integer division
Description
intdiv
( int
$dividend
, int $divisor
) : int
Returns the integer quotient of the division of dividend by divisor.
Parameters
-
dividend -
Number to be divided.
-
divisor -
Number which divides the
dividend.
Return Values
The integer quotient of the division of dividend by divisor.
Errors/Exceptions
If divisor is 0, a DivisionByZeroError
exception is thrown. If the dividend is PHP_INT_MIN
and the divisor is -1, then an
ArithmeticError exception is thrown.
Examples
Example #1 intdiv() example
<?php
var_dump(intdiv(3, 2));
var_dump(intdiv(-3, 2));
var_dump(intdiv(3, -2));
var_dump(intdiv(-3, -2));
var_dump(intdiv(PHP_INT_MAX, PHP_INT_MAX));
var_dump(intdiv(PHP_INT_MIN, PHP_INT_MIN));
var_dump(intdiv(PHP_INT_MIN, -1));
var_dump(intdiv(1, 0));
?>
int(1) int(-1) int(-1) int(1) int(1) int(1) Fatal error: Uncaught ArithmeticError: Division of PHP_INT_MIN by -1 is not an integer in %s on line 8 Fatal error: Uncaught DivisionByZeroError: Division by zero in %s on line 9
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User Contributed Notes 4 notes
AmeenRoss ¶
4 years ago
polettog at gmail dot com ¶
4 years ago
Without intdiv(), the following may be a good way (with $a and $b of type integer and not too big) :
<?php
(int)($a / $b)
?>
because in case of divisible integers, the result will be integer and there is no risk of float appearing round but below their represented value (like the case (0.1+0.7)*10).
$a and $b really needs to be of type integer though.
If they are too big and indivisible, some precision will be lost during the conversion to float and the result may be inaccurate.
Ts.Saltan ¶
4 years ago
$a = 57;
$b = 3;
var_dump(
intdiv($a,$b),
intdiv_1($a,$b),
intdiv_2($a,$b)
);
function intdiv_1($a, $b){
return ($a-$a%$b)/$b;
}
function intdiv_2($a, $b){
return floor($a/$b);
}
//intdiv($a, $b) == floor($a/$b) == ($a-$a%$b)/$b
Bubonic dot pestilence at gmail dot com ¶
3 years ago
<?php
function intdiv_2($a, $b) {
$val = $a / $b;
return ($val < 0 ? "ceil" : "floor") ($val);
}
?>
Aren't this?!
